The alkali metals dissolve in liquid ammonia giving deep blue solutions which are conducting in nature.
\( M + (x + y ) NH_3 \rightarrow [ M (NH_3)_x]^+ + [ e (NH_3)_y ]^-\)
What is x and y in the above equation?
How to interpret the above chemical equation?
Dissolution of alkali metals in liquid ammonia
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- Dhamnekar Winod
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Dissolution of alkali metals in liquid ammonia
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
- ChenBeier
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Re: Dissolution of alkali metals in liquid ammonia
It can be every number.
At least its Na => Na+ + e-
Sodium and the electron are solvated in ammonia.
At least its Na => Na+ + e-
Sodium and the electron are solvated in ammonia.
- Dhamnekar Winod
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Re: Dissolution of alkali metals in liquid ammonia
So, (x + y) is a stoichiometry coefficient. Isn't it?
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
- ChenBeier
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Re: Dissolution of alkali metals in liquid ammonia
You can say so
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Re: Dissolution of alkali metals in liquid ammonia
Have solution?
- ChenBeier
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Re: Dissolution of alkali metals in liquid ammonia
Its written above x,y € Re.
Can be every number.
Can be every number.