## Amount of solvent

Chemistry and homework help forum.

Organic Chemistry, Analytical Chemistry, Biochemistry, Physical Chemistry, Computational Chemistry, Theoretical Chemistry, High School Chemistry, Colledge Chemistry and University Chemistry Forum.

Share your chemistry ideas, discuss chemical problems, ask for help with scientific chemistry questions, inspire others by your chemistry vision!

Please feel free to start a scientific chemistry discussion here!

Discuss chemistry homework problems with experts!

Ask for help with chemical questions and help others with your chemistry knowledge!

Moderators: Xen, expert, ChenBeier

Talal
Full Member
Posts: 11
Joined: Sun Sep 12, 2021 10:26 am

### Amount of solvent

I have this balanced reaction:
Y2O3 + 6HNO3 = 2Y(NO3)3 + 3H2O
How I can determine the amount of HNO3 (solvent)?
Thanks
ChenBeier
Distinguished Member
Posts: 1107
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

### Re: Amount of solvent

You have a ratio 1:6 for Yttriumoxide and nitric acid. So you have to know how much Yttriumoxide you want to dissolve. You calculate the mole of it and know you need 6 times more of the nitric acid. According the concentration and specific gravity you can convert the mole of nitric acid to the volume.
Talal
Full Member
Posts: 11
Joined: Sun Sep 12, 2021 10:26 am

### Re: Amount of solvent

Okay, So I have 0.002 mole of yttriumoxide that means I should have 0.012 mole of nitric acid, Please can you tell me how I can calculate the amount of nitric acid.
ChenBeier
Distinguished Member
Posts: 1107
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

### Re: Amount of solvent

You need m = n* M ( moles time molar mass) this gives 100% HNO3 , divided by the perecentage of it you get the Real mass and then V = m/σ. σ is specific gravity of nitric.
Talal
Full Member
Posts: 11
Joined: Sun Sep 12, 2021 10:26 am

Thanks