A 30,0 g de una muestra de ZnCl2 se le agrega exceso de H3PO4 obteniéndose 15,5 g de Zn3(PO4)2.
Calcule los equivalentes de H3PO4 que deben haber reaccionado si el rendimiento fue del 90,0 %
Me podrian ayudar
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Re: Me podrian ayudar
Excess H3PO4 is added to 30.0 g of a sample of ZnCl2, obtaining 15.5 g of Zn3 (PO4) 2.
Calculate the H3PO4 equivalents that must have reacted if the yield was 90.0%
Calculate the H3PO4 equivalents that must have reacted if the yield was 90.0%
- ChenBeier
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Re: Me podrian ayudar
What is your own work. Where do you have problems.
Re: Me podrian ayudar
I don't know how to get the excess H3PO4 ...
Idk to pose the first part of the problem
Idk to pose the first part of the problem
- ChenBeier
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Re: Me podrian ayudar
Excess means there is enough phosphoric acid.
First develop the chemical equation.
Then calculate the mol of zincphosphate .
Check is enough zinc chloride available.
From zinc phosphate calculate back how much phosphoric is needed.
Calculate with the yield.
First develop the chemical equation.
Then calculate the mol of zincphosphate .
Check is enough zinc chloride available.
From zinc phosphate calculate back how much phosphoric is needed.
Calculate with the yield.