I need some help, how do I ajust this ecuation with redox method?
H2S + NaCr2O7 + H2SO4 = Cr2(SO4)3 + NaHSO4 + S + H2O
Thanks.
Redox
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Separate to redox parts
H2S/ S and Cr2O7 2- / Cr3+
Oxidation: H2S => 2 H+ + 2 e- + S
Reduction: Cr2O7 2- + 14 H+ + 6 e- => 2 Cr3+ + 7 H2O
Balance electrons
3 H2S => 6 H+ + 6 e- + 3 S
Addition
Cr2O7 2- + 3 H2S + 8 H+ => 2 Cr3+ + 3 S + 7 H2O
Add of Na+ and SO4 2-
Na2Cr2O7 + 3 H2S + 4 H2SO4 => Cr2(SO4)3 + 3 S + Na2SO4 + 7 H2O
H2S/ S and Cr2O7 2- / Cr3+
Oxidation: H2S => 2 H+ + 2 e- + S
Reduction: Cr2O7 2- + 14 H+ + 6 e- => 2 Cr3+ + 7 H2O
Balance electrons
3 H2S => 6 H+ + 6 e- + 3 S
Addition
Cr2O7 2- + 3 H2S + 8 H+ => 2 Cr3+ + 3 S + 7 H2O
Add of Na+ and SO4 2-
Na2Cr2O7 + 3 H2S + 4 H2SO4 => Cr2(SO4)3 + 3 S + Na2SO4 + 7 H2O