CuSCN + KIO3 + HCl = CuSO4 + KCl + HCN + ICl + H2O
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Neon
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CuSCN + KIO3 + HCl = CuSO4 + KCl + HCN + ICl + H2O


How do I edit this chemical equation? I ask for the procedure.

CuSCN + KIO3 + HCl = CuSO4 + KCl + HCN + ICl + H2O

Thank you in advance! Very Happy
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ChenBeier
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First you have to check what will be oxidiesed and what will be reduced.

Oxidiesed Cu+ => Cu 2+

SCN- => SO42- + CN-

Redused: IO3- => I+ !! later ICl will beformed

Develop for this the half reaction.
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ChenBeier
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As present here is the solution

4 CuSCN +7 KIO3 + 14 HCl => 4 CuSO4 + 7 KCl + 4 HCN + 7 ICl + 5 H2O
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