Hello
?KNO3+?C12H22O11=?K2O+?N2+?H2O+50% CO+50% CO2
How balance chemical equation
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- ChenBeier
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36 KNO3 + 5 C12H22O11 => 18 K2O + 18 N2 + 55 H2O + 30 CO2 + 30 CO
How balance chemical equation
Hi Chen. How did you do that? Manually.ChenBeier wrote:Code: Select all
36 KNO3 + 5 C12H22O11 => 18 K2O + 18 N2 + 55 H2O + 30 CO2 + 30 CO
Regards Zbych
- ChenBeier
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- Joined: Wed Sep 27, 2017 7:25 am
- Location: Berlin, Germany
You have to develop the oxidation and reduction equation first.
sugar you can change to
Then you take each 6 C to oxidize to and CO
The reduction is
The combination guides to the result.
sugar you can change to
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C12 (H2O)11
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CO2
The reduction is
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2 KNO3 => N2 + K2O + 5 (O)