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Newbie

Joined: 17 Jan 2016
Posts: 1
 Posted: Sun Jan 17, 2016 11:20 pm    Post subject: HO2-(aq) + MnO4-(aq) = MnO2(s) + O2(g) I am completely stumped on how to balance this equation, can I get some advice on how to solve it? Thanks. HO2-(aq) + MnO4-(aq) = MnO2(s) + O2(g)

Newbie

Joined: 18 Jan 2016
Posts: 4
 Posted: Wed Jan 20, 2016 6:10 am    Post subject: First it seems the equation might be incomplete seeing as the hydrogen atom specified isnt used, secondly i think you ment ho2 to be H2O2 - hydrogen peroxyde, in that case the equation is as follows: 2-H2O2(aq) + MnO4(aq) = MnO2(s) + 2-O2(g) + 2-H2O(l)

Full Member

Joined: 21 Aug 2017
Posts: 10
Posted: Mon Aug 21, 2017 5:31 am    Post subject:

 matej789 wrote: First it seems the equation might be incomplete seeing as the hydrogen atom specified isnt used, secondly i think you ment ho2 to be H2O2 - hydrogen peroxyde, in that case the equation is as follows: 2-H2O2(aq) + MnO4(aq) = MnO2(s) + 2-O2(g) + 2-H2O(l)

That was interesting
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