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Joined: 05 Jan 2017
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# Can someone explain me how to balance this reaction?

(Ru++) +(NH4+) + (Br2) = (Br-) +Ru(NO2)2

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Joined: 27 Oct 2014
Posts: 110

# can we know the source for this reaction

can we know the source for this reaction

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Joined: 19 Mar 2012
Posts: 396

# Re: Can someone explain me how to balance this reaction?

 Di Mezza Alfredo wrote: (Ru++) +(NH4+) + (Br2) = (Br-) +Ru(NO2)2

Todo, balance:
• Ru{2+} + NH4{+} + Br2 = Br{-} + Ru(NO2)2

Remove the spectator ion Ru{2+} and divide into Red/Ox half cells.
• 2 NH4{+} = 2 NO2{-}
• Br2 = 2 Br{-}

Balance O with water
• 2 NH4{+} + 4 H2O = 2 NO2{-}
• Br2 = 2 Br{-}

Balance H with protons
• 2 NH4{+} + 4 H2O = 2 NO2{-} + 16 H{+}
• Br2 = 2 Br{-}

Migrate to basic
• 2 NH4{+} + 16 OH{-} = 2 NO2{-} + 12 H2O
• Br2 = 2 Br{-}

Balance charge with electrons
• 2 NH4{+} + 16 OH{-} = 2 NO2{-} + 12 H2O + 12 e{-}
• 6 Br2 + 12 e{-} = 12 Br{-}

Recombine:
• Ru{2+} + 2 NH4{+} + 16 OH{-} + 6 Br2 = Ru(NO2)2 + 12 Br{-} + 12 H2O

Jr. Member

Joined: 21 Aug 2017
Posts: 9

# Re: Can someone explain me how to balance this reaction?

GrahamKemp wrote:
 Di Mezza Alfredo wrote: (Ru++) +(NH4+) + (Br2) = (Br-) +Ru(NO2)2

Todo, balance:
• Ru{2+} + NH4{+} + Br2 = Br{-} + Ru(NO2)2

Remove the spectator ion Ru{2+} and divide into Red/Ox half cells.
• 2 NH4{+} = 2 NO2{-}
• Br2 = 2 Br{-}

Balance O with water
• 2 NH4{+} + 4 H2O = 2 NO2{-}
• Br2 = 2 Br{-}

Balance H with protons
• 2 NH4{+} + 4 H2O = 2 NO2{-} + 16 H{+}
• Br2 = 2 Br{-}

Migrate to basic
• 2 NH4{+} + 16 OH{-} = 2 NO2{-} + 12 H2O
• Br2 = 2 Br{-}

Balance charge with electrons
• 2 NH4{+} + 16 OH{-} = 2 NO2{-} + 12 H2O + 12 e{-}
• 6 Br2 + 12 e{-} = 12 Br{-}

Recombine:
• Ru{2+} + 2 NH4{+} + 16 OH{-} + 6 Br2 = Ru(NO2)2 + 12 Br{-} + 12 H2O

The information available was very useful
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