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Chemist wanted to check the condition of crystal water in
K2SO4 * Cr2(SO4)3 * 24 H2O
which has long stayed in laboratory.
In this purpose, he made 95.2 g of that solution ( K2SO4 * Cr2(SO4)3 * 24 H2O) and of volume 1104 cm3. Then in 237 cm3 of the same solution ( K2SO4 * Cr2(SO4)3 * 24 H2O) he added solution of (Ba(NO3)2) and it separated 19.6 g sediment.
Instead of 24, how many crystal water this solution constisted of?
