help with balancing
Moderators: Xen, expert, ChenBeier
help with balancing
what i one way to balance 2C8 H18 + O2 = CO + H2O
-
- Distinguished Member
- Posts: 396
- Joined: Mon Mar 19, 2012 10:12 pm
Re: help with balancing
Step by step.
(1) Partial Oxidation (produces carbon monoxide)
x C8H18 + y O2 = z CO + w H2O
Balance C: z = 8x.
Balance H: 2w = 18x, or w = 9x.
x C8H18 + y O2 = 8x CO + 9x H2O
Balance O: 2y = 8x + 9x, or 2y = 17x.
Lowest Integer Solution: y = 17, x = 2
2 C8H18 + 17 O2 = 16 CO + 18 H2O
(2) Complete Oxidation (produces carbon dioxide)
You just need an extra 16 O (as 8 O2) to produce 16 CO2 instead of 16 CO.
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O
(1) Partial Oxidation (produces carbon monoxide)
x C8H18 + y O2 = z CO + w H2O
Balance C: z = 8x.
Balance H: 2w = 18x, or w = 9x.
x C8H18 + y O2 = 8x CO + 9x H2O
Balance O: 2y = 8x + 9x, or 2y = 17x.
Lowest Integer Solution: y = 17, x = 2
2 C8H18 + 17 O2 = 16 CO + 18 H2O
(2) Complete Oxidation (produces carbon dioxide)
You just need an extra 16 O (as 8 O2) to produce 16 CO2 instead of 16 CO.
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O