Latimer diagram

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07xaca
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Joined: Thu Nov 24, 2011 8:48 am

Latimer diagram

Post by 07xaca »

The following Latimer diagram is known for the metal M in acid solution.

MO3 (s) -> MO2 (s) -> M3+ (aq) -> M2+ (aq) -> M(s)
-------(+0,50 V)----(+0,40 V)------(-0,20 V)-----(-0,05V)

-Indicate with an explanation and response form, which of the compound (s) or ions (s) mentioned in above Latimer diagram that can be disproportionate.

The rule is that: if the potential to the right of the species is higher than the potential on the left, it will disproportionate.

But as I can see, no compounds or ions are disproportionate. Is that true ?
expert
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Post by expert »

Many elements and their oxides or acid forms can disproportionate, and these processes even happen in the environment. Sulfur is a good example http://www.iapws.jp/Proceedings/Symposium05/365Lin.pdf

Another example of sulfur disproportioning is the following reaction of sodium dithionite (or hydrosulfite) in water or in the presence of acid http://www.inchem.org/documents/sids/sids/7775146.pdf
2 Na2S2O4 + H2O → 2 NaHSO3 + Na2S2O3
In acidic medium: 2 H2S2O4 → 3 SO2 + S + 2 H2O
In strongly acidic medium: 3 H2S2O4 → 5 SO2 + H2S + 2 H2O


or similar for sodium thiosulfate
Na2S2O3 + 2 HCl = H2O + 2 NaCl + S + SO2

Elementary phosphorous (usually white) and phosphorous (3+) compounds disproportionate too.
http://www.arkat-usa.org/get-file/19305/

P4 + NaOH = PH3 + NaH2PO2
http://it.answers.yahoo.com/question/in ... 838AA3gVLm


Keep looking on your own. You’ll find plenty other examples.
:D
Remember safety first! Check MSDS and consult with professionals before performing risky experiments.
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