Hi all,
i've carried out the titration of H3PO4 with NaOH followed by the indicator pT 5.1 and 9.9. What i've recorded is the V(Naoh) for pT 5.1 is 8.500 ml, V(NaOH) for pT 9.9 is 19,00 ml. In my opinion, i think the value using pT 9.9 is better because the pH at equivalence is 1/2(pKa2 + pKa3) ~ 9.77 so it might be better. Therefore, the V(NaOH) = 19,00 ml is more reliable. Am i right ? Could someone help me !!!
Thanks !
TITRATION AND INDICATOR [ANALYTICAL CHEMISTRY]
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- ChenBeier
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Re: TITRATION AND INDICATOR [ANALYTICAL CHEMISTRY]
I think it doesn't matter.
In one case you titrate NaOH + H3PO4 => NaH2PO4 + H2O consumption 8.5 ml
In the other case you got 2 NaOH + H3PO4 => Na2HPO4 + 2 H2O consumption 19 ml
What is meant with pT 5.1 and 9.9?
Normaly the consumption should be only 17 ml or the first value 9.5 ml.
In one case you titrate NaOH + H3PO4 => NaH2PO4 + H2O consumption 8.5 ml
In the other case you got 2 NaOH + H3PO4 => Na2HPO4 + 2 H2O consumption 19 ml
What is meant with pT 5.1 and 9.9?
Normaly the consumption should be only 17 ml or the first value 9.5 ml.
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Re: TITRATION AND INDICATOR [ANALYTICAL CHEMISTRY]
I think the V(NaOH) = 19.00 ml is a more reliable measure of the concentration of H3PO4 because it is closer to the true equivalence point, right?