Strongest reducing potential
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Strongest reducing potential
The stronger the reducing potential, the more likely to oxidise. The more likely to oxidise, the lower the standard reduction potential. In the question and worked solution below, it states that the larger the standard reduction potential, the stronger the reducing potential. Is this wrong or am I misunderstanding? Shouldn’t the order of strongest to weakest reducing potential be Mn2+, Mn, MnO4-, opposite the answer?
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- ChenBeier
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Re: Strongest reducing potential
No you have to write all equations as Reduction
MnO4- + 8 H+ + 5 e- => Mn 2+ + 4 H2O + 1,51 V
Mn 2+ + 2 e- => Mn - 1,18 V
Mn + e- => not possible.
So Permanganate can be reduced to Mn 2+ in this again to Mn
The order is MnO4- , Mn 2+
Mn has no reducing potential because it cannot reduced further.
In manganese metal the oxidation number is 0, the lowest point for metals normaly. In Mn 2+ its +2 and in MnO4- its +7.
MnO4- + 8 H+ + 5 e- => Mn 2+ + 4 H2O + 1,51 V
Mn 2+ + 2 e- => Mn - 1,18 V
Mn + e- => not possible.
So Permanganate can be reduced to Mn 2+ in this again to Mn
The order is MnO4- , Mn 2+
Mn has no reducing potential because it cannot reduced further.
In manganese metal the oxidation number is 0, the lowest point for metals normaly. In Mn 2+ its +2 and in MnO4- its +7.