Hi,
is this the correct balance equation for substitution reaction between 1,3,5-trimethylbenzene tricarbonyl molybdenum and triphenylphosphone?
(C6H3Me3)Mo(CO)3 + 3Ph3P = (C6H3Me3)Mo(Ph3P)3 + 3CO
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Re: (C6H3Me3)Mo(CO)3 + 3Ph3P = (C6H3Me3)Mo(Ph3P)3 + 3CO
If there is enough space? I would think to substitute only two phosphans.
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Re: (C6H3Me3)Mo(CO)3 + 3Ph3P = (C6H3Me3)Mo(Ph3P)3 + 3CO
so it will be (C6H3Me3)Mo(CO)3 + 3Ph3P = (C6H3Me3)Mo(CO)(Ph3P)2 + Ph3P + CO2 ????
i am sorry i am kinda slow in balancing the equation
i am sorry i am kinda slow in balancing the equation
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Re: (C6H3Me3)Mo(CO)3 + 3Ph3P = (C6H3Me3)Mo(Ph3P)3 + 3CO
C6H3Me3)Mo(CO)3 + 3Ph3P = (C6H3Me3)Mo(CO)(Ph3P)2 + Ph3P + CO2 ????
No, check balancing. There is no CO2 and you can erase one Phosphan.
No, check balancing. There is no CO2 and you can erase one Phosphan.
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Re: (C6H3Me3)Mo(CO)3 + 3Ph3P = (C6H3Me3)Mo(Ph3P)3 + 3CO
C6H3Me3)Mo(CO)3 + 3Ph3P = (C6H3Me3)Mo(CO)(Ph3P)2 + Ph3P + CO2 ????
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Re: (C6H3Me3)Mo(CO)3 + 3Ph3P = (C6H3Me3)Mo(Ph3P)3 + 3CO
Why repeating the wrong answer.