Unknown products (once again)

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kingon
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Unknown products (once again)

Post by kingon »

Once again I ask whether someone has an idea how to finish this reaction. Thanks in advance for help.
[Cd(NH3)4](OH)2 + (NH4)2S = CdS + ...
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ChenBeier
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Re: Unknown products (once again)

Post by ChenBeier »

[Cd(NH3)4](OH)2 + (NH4)2S = CdS + 6 NH3 + 2 H2O
EMUT_COSMOS
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Re: Unknown products (once again)

Post by EMUT_COSMOS »

Maybe we should check if the reaction is an exothermic reaction. If yes, there will be NH3. If not, there will be only NH3·H2O left in the solution.
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ChenBeier
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Re: Unknown products (once again)

Post by ChenBeier »

It was the question which products are formed, there is more NH3 as H2O. It was not told if everything takes place in water.
If so it would be
Cd(NH3)4](OH)2 + (NH4)2S + 4 H2O => CdS + 6 NH3* H2O
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