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Unknown products (once again)
Posted: Sun Oct 30, 2022 4:38 am
by kingon
Once again I ask whether someone has an idea how to finish this reaction. Thanks in advance for help.
[Cd(NH3)4](OH)2 + (NH4)2S = CdS + ...
Re: Unknown products (once again)
Posted: Sun Oct 30, 2022 6:44 am
by ChenBeier
[Cd(NH3)4](OH)2 + (NH4)2S = CdS + 6 NH3 + 2 H2O
Re: Unknown products (once again)
Posted: Sun Nov 06, 2022 7:59 am
by EMUT_COSMOS
Maybe we should check if the reaction is an exothermic reaction. If yes, there will be NH3. If not, there will be only NH3·H2O left in the solution.
Re: Unknown products (once again)
Posted: Sun Nov 06, 2022 10:37 am
by ChenBeier
It was the question which products are formed, there is more NH3 as H2O. It was not told if everything takes place in water.
If so it would be
Cd(NH3)4](OH)2 + (NH4)2S + 4 H2O => CdS + 6 NH3* H2O