## balancing equations

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ninzz0
Newbie
Posts: 2
Joined: Thu Oct 20, 2022 4:36 am

### balancing equations

1.99 g of magnesium hydrogencarbonate was added to a 2.118 mol/L solution of acetic acid, CH₃COOH in water (50.0 mL), producing carbon dioxide gas, water and magnesium acetate, Mg(CH3COO)2.
- Write a balanced chemical equation for the reaction

I've tried doing this manually and it doesnt work and the calculator says its impossible but its a question on a practice exam from my university, can someone help me solve it
ChenBeier
Distinguished Member
Posts: 1205
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

### Re: balancing equations

MgH2(CO3)2 + 2 CH3COOH => Mg(CH3COO)2 + 2 H2O + 2 CO2

ninzz0
Newbie
Posts: 2
Joined: Thu Oct 20, 2022 4:36 am

### Re: balancing equations

ChenBeier wrote: Thu Oct 20, 2022 9:07 am MgH2(CO3)2 + 2 CH3COOH => Mg(CH3COO)2 + 2 H2O + 2 CO2

Can you explain how have you gotten that? Do you not begin this with this?

MgH2(CO3)2 + CH3COOH => Mg(CH3COO)2 + CO2

Theres water on both sides so dont they cancel out and get removed?
ChenBeier
Distinguished Member
Posts: 1205
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

### Re: balancing equations

No. Your equation isn't balanced. There is no water on both sites, to less acetic acid and to much hydrogen on left side.