Chemistry Forum

Trying to balance chromium reduction reaction :
Sodium Hydrosulfide (basic pH) + Sodium Chromate > Chromium Hydroxide solid (precipitates if alkaline) + Sodium Sulfate
NaHS + NaCrO₄ = Cr(OH)₃ + Na₂SO₄
or for calculator
NaHS + NaCrO₄ = CrO₃H₃ + Na₂SO₄
What did I miss ? Thanks guys

The formula of sodium chromate is wrong and you missed water and hydroxide.

HS- + 9 OH- => SO₄ 2- + 5 H₂O + 8 e- Oxidation

CrO₄ 2- + 4 H₂O + 3 e- => Cr(OH)₃ + 5 OH- Reduktion

Continue with this