_{3})

_{2}*4H

_{2}O and P

_{2}O

_{5}and I need to have the molar ratio of Ca/P = 1.5

I wonder how could I do that?

Thank you for your help

**Moderators:** Xen, expert, ChenBeier

I am currently using Ca(NO_{3})_{2}*4H_{2}O and P_{2}O_{5} and I need to have the molar ratio of Ca/P = 1.5

I wonder how could I do that?

Thank you for your help

I wonder how could I do that?

Thank you for your help

- ChenBeier
- Distinguished Member
**Posts:**1173**Joined:**Wed Sep 27, 2017 7:25 am**Location:**Berlin, Germany

You need 1 mol of the Calcium nitrate tetra hydrate and 0.333 mol of the phosphorous Penta oxide.

One 1 mol Ca(NO_{3})_{2}*4H_{2}O correspond to 1 mol Ca

and 1 mol P_{2}O_{5} correspond to 2 mol P

Ratio Ca/P = 1.5 = 1/0,666 mol = 1 Ca(NO_{3})_{2}*4H_{2}O /0,333 P_{2}O_{5}

With the molar mass of each component you can calculate the mass in g.

One 1 mol Ca(NO

and 1 mol P

Ratio Ca/P = 1.5 = 1/0,666 mol = 1 Ca(NO

With the molar mass of each component you can calculate the mass in g.

Hi there,ChenBeier wrote: ↑Mon Jun 20, 2022 11:35 am You need 1 mol of the Calcium nitrate tetra hydrate and 0.333 mol of the phosphorous Penta oxide.

One 1 mol Ca(NO_{3})_{2}*4H_{2}O correspond to 1 mol Ca

and 1 mol P_{2}O_{5}correspond to 2 mol P

Ratio Ca/P = 1.5 = 1/0,666 mol = 1 Ca(NO_{3})_{2}*4H_{2}O /0,333 P_{2}O_{5}

With the molar mass of each component you can calculate the mass in g.

Thank you very much for your reply, I found out I need to mix 236.15g of Calcium Nitrate Tera Hydrate with 94.53537g of Phosphorous Penta Oxide ratio in order to produce Ca/P = 1.5

Another quick question, there's this literature I have been reading and it suggested me to dissolve Ca(NO

Thank you again for your help.

- ChenBeier
- Distinguished Member
**Posts:**1173**Joined:**Wed Sep 27, 2017 7:25 am**Location:**Berlin, Germany

The calculation for P_{2}O_{5} is wrong its only 47,328 g

Molar weight of P_{2}O_{5} is 142 g/ mol. Multiplied with 0.3333 is 47.3286 g

The other answer is

1 mol to 0.333 mol can also diluted down

In this case 0.01 mol to 0.0033 mol

What means in mass 2,36 g Calcium Nitrate tetra hydrate and 0,473 g Phosphorous penta oxide

Molar weight of P

The other answer is

1 mol to 0.333 mol can also diluted down

In this case 0.01 mol to 0.0033 mol

What means in mass 2,36 g Calcium Nitrate tetra hydrate and 0,473 g Phosphorous penta oxide

Thank you for the correction, I was looking at the PChenBeier wrote: ↑Mon Jun 20, 2022 2:03 pm The calculation for P_{2}O_{5}is wrong its only 47,328 g

Molar weight of P_{2}O_{5}is 142 g/ mol. Multiplied with 0.3333 is 47.3286 g

The other answer is

1 mol to 0.333 mol can also diluted down

In this case 0.01 mol to 0.0033 mol

What means in mass 2,36 g Calcium Nitrate tetra hydrate and 0,473 g Phosphorous penta oxide

For the dissolve in absolute ethanol to form 0.01 mol (Calcium Nitrate Tetrahydrate) and 0.003 mol (phosphorous pentoxide), which equation I can use to find how much mass in how much volume of ethanol to dissolve to desire mol?

- ChenBeier
- Distinguished Member
**Posts:**1173**Joined:**Wed Sep 27, 2017 7:25 am**Location:**Berlin, Germany

It is the same equation like above. I wrote the result already. It is only 1/100 of the calculated value.

Moles = mass/ Molar mass, n = m/M

In case of P_{4}O_{10} is the result more worse, because 1 mol P_{4}O_{10} = 4 mol P

It is more worse then 1/0.166666 Ca/P_{4}O_{10} = 1/4*0,16666 Ca/P = 1/0,66666 = 1.5

The mass will be still the same either calculated as P_{2}O_{5} or P_{4}O_{10} 47,3 g.

The volume is calculated to 1 Liter. Concentration normaly given as mol/l.

Moles = mass/ Molar mass, n = m/M

In case of P

It is more worse then 1/0.166666 Ca/P

The mass will be still the same either calculated as P

The volume is calculated to 1 Liter. Concentration normaly given as mol/l.

Hi there,ChenBeier wrote: ↑Mon Jun 20, 2022 10:12 pm It is the same equation like above. I wrote the result already. It is only 1/100 of the calculated value.

Moles = mass/ Molar mass, n = m/M

In case of P_{4}O_{10}is the result more worse, because 1 mol P_{4}O_{10}= 4 mol P

It is more worse then 1/0.166666 Ca/P_{4}O_{10}= 1/4*0,16666 Ca/P = 1/0,66666 = 1.5

The mass will be still the same either calculated as P_{2}O_{5}or P_{4}O_{10}47,3 g.

The volume is calculated to 1 Liter. Concentration normaly given as mol/l.

As long as I use Ca/P = 1.5 it would work out well, right? either: 1/0.333 or, 0.01/0.0033, etc... But since the literature suggested to dissolved down to 0.01 and 0.0033 in absolute ethanol, Ca and P respectively. It means that I would need to dissolve 2.36g Ca(NO

Quoted Synthesis of B-tricalcium phosphate by H. Chaair, H. Labjar , O. Britel

"Calcium nitrate tetrahydrate (Ca(NO)

- ChenBeier
- Distinguished Member
**Posts:**1173**Joined:**Wed Sep 27, 2017 7:25 am**Location:**Berlin, Germany

Its only a diluted solution nothing else. You can choose any amount only to achieve Ca/P = 1.5. Maybe its also a matter of soloubility. I would go according the receipe.