Stoichiometry - calculation problem

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ned_yas
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Stoichiometry - calculation problem

Post by ned_yas »

Hi folks,

would like to verify the following calculation:
How much 63 % HNO3 will the yield be from 1 700 tonnes NH3 (for 24 hours process): НN3 --> A --> B --> HNO3

Synthesis equations (Ostwald process):
4NH3 + 5O2 --> 4NO + 6H2O
2NO + O2 --> N2O4
3N2O4 + 2H2O --> 4HNO3 + 2NO

moles NH3:HNO3 = 1:1
n (NH3) = 100 mole => 6 300 tonnes HNO3

Is this correct?

Thanks for helping,
Ned
Last edited by ned_yas on Wed Apr 20, 2022 12:21 pm, edited 1 time in total.
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ChenBeier
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Re: Stoichiometry - calculation probleme

Post by ChenBeier »

You had forgotten the Percentage of the nitric acid.
ned_yas
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Re: Stoichiometry - calculation probleme

Post by ned_yas »

what do you mean - could you please explain the mistake I do? Thanks, N.

1 700 t NH3 / 17 = 100 mole NH3
m(HNO3) = 100 mole * 63 = 6 300 t HNO3
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ChenBeier
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Re: Stoichiometry - calculation probleme

Post by ChenBeier »

6300 t is 100% HNO3. But the acid is only 63%. w.w. So how much you will get.
ned_yas
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Re: Stoichiometry - calculation probleme

Post by ned_yas »

6 300 т --> 100 % acid
x t --> 63 % => 3 969 t 63 % HNO3

correct?
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ChenBeier
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Re: Stoichiometry - calculation problem

Post by ChenBeier »

No the 63% is not the yield its the concentration. The amount must be higher. Its the opposit 10000 t 63% acid contain 6300 t 100%.
ned_yas
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Re: Stoichiometry - calculation problem

Post by ned_yas »

Oh, of course, the diluted acid will be more... My silly mistake :) Thanks a lot!
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