I'm working on preparing CuS particles and having hard time balancing the reaction of:
Cu(CH3COO).2H2O + Na2S2O3.5H2O
Balance the Reaction
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- ChenBeier
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Re: Balance the Reaction
Disproportion of thiosulfate
5H2O + S2O3 2- => 2 SO4 2- + 10 H+ + 8 e- Oxidation
6 H+ + S2O3 2- + 8 e- => 2 S 2- + 3 H2O Reduktion
2 H2O + 2 S2O3 2- => 2 SO4 2- + 2 S 2- + 4 H+ sum
H2O + S2O3 2- => SO4 2- + S 2- + 2 H+ divided by 2
The S 2- react with the Cu 2+ to CuS
5H2O + S2O3 2- => 2 SO4 2- + 10 H+ + 8 e- Oxidation
6 H+ + S2O3 2- + 8 e- => 2 S 2- + 3 H2O Reduktion
2 H2O + 2 S2O3 2- => 2 SO4 2- + 2 S 2- + 4 H+ sum
H2O + S2O3 2- => SO4 2- + S 2- + 2 H+ divided by 2
The S 2- react with the Cu 2+ to CuS
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Re: Balance the Reaction
will me reaction be affected if I use copper acetate dihydrate instead of copper acetate monohydrate
- ChenBeier
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Re: Balance the Reaction
No. Its All spectator ions.
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Re: Balance the Reaction
Thank u so much. i was getting lesser product with dihydrate. thanks again
- ChenBeier
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Re: Balance the Reaction
Of course you have to do the right calculation. 1 g mono Hydrate is not the same like 1 g dihydrate. You have to convert the mass via the moles.