How is the balance of the equation that has this special case of hydrogen peroxide
Como é o balanceamento dessa equação que tem esse caso especial da água oxigenada
KMnO4 + H2O2 + H2SO4 = K2SO4 + MnSO4 + H2O + O2
Balanceamento por oxirredução
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- ChenBeier
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Re: Balanceamento por oxirredução
Redox pair MnO4-/Mn 2+ and H2O2/ O2
Reduction in acidic conditions MnO4- + 8 H+ + 5 e- => Mn 2+ + 4 H2O
Oxidation H2O2 => 2 H+ + 2 e- + O2
Multiplikation of equations
2 MnO4- + 16 H+ + 10 e- => 2 Mn 2+ + 8 H2O
5 H2O2 => 10 H+ + 10 e- + 5 O2
Addition
2 MnO4- + 6H+ + 5 H2O2 => 2 Mn 2+ + 8 H2O + 5 O2
K+ and SO4 2- are spectator ions.
2 KMnO4 + 3 H2SO4 + 5 H2O2 => 2 MnSO4 + K2SO4 + 8 H2O + 5 O2
Reduction in acidic conditions MnO4- + 8 H+ + 5 e- => Mn 2+ + 4 H2O
Oxidation H2O2 => 2 H+ + 2 e- + O2
Multiplikation of equations
2 MnO4- + 16 H+ + 10 e- => 2 Mn 2+ + 8 H2O
5 H2O2 => 10 H+ + 10 e- + 5 O2
Addition
2 MnO4- + 6H+ + 5 H2O2 => 2 Mn 2+ + 8 H2O + 5 O2
K+ and SO4 2- are spectator ions.
2 KMnO4 + 3 H2SO4 + 5 H2O2 => 2 MnSO4 + K2SO4 + 8 H2O + 5 O2
Re: Balanceamento por oxirredução
Muito obrigada, entendi
Re: Balanceamento por oxirredução
ChenBeier wrote: ↑Sat Apr 16, 2022 2:09 am Redox pair MnO4-/Mn 2+ and H2O2/ O2
Reduction in acidic conditions MnO4- + 8 H+ + 5 e- => Mn 2+ + 4 H2O
Oxidation H2O2 => 2 H+ + 2 e- + O2
Multiplikation of equations
2 MnO4- + 16 H+ + 10 e- => 2 Mn 2+ + 8 H2O
5 H2O2 => 10 H+ + 10 e- + 5 O2
Addition
2 MnO4- + 6H+ + 5 H2O2 => 2 Mn 2+ + 8 H2O + 5 O2
K+ and SO4 2- are spectator ions.
2 KMnO4 + 3 H2SO4 + 5 H2O2 => 2 MnSO4 + K2SO4 + 8 H2O + 5 O2
- Good morning, after I posted this question, I tried to redo it yesterday and I managed to do it in a way without setting up these equations in acidic conditions. Can you tell me if always the reduction in acidic conditions the H + will be in the reactants and the H2O in the products. In the oxidation under acidic conditions, will the H + be in the product together with the O2?
- ChenBeier
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Re: Balanceamento por oxirredução
Yes there is a law
Acidic conditions
Reduction: if oxygen is in the reaction, then H+ is added on reactant side and water is obtained on product side
Oxidation is vise versa
Alkaline conditions
Reduction: if oxygen is in the reaction, then water is added on reactant side and OH- is obtained on product side
Oxidation is vise versa
Acidic conditions
Reduction: if oxygen is in the reaction, then H+ is added on reactant side and water is obtained on product side
Oxidation is vise versa
Alkaline conditions
Reduction: if oxygen is in the reaction, then water is added on reactant side and OH- is obtained on product side
Oxidation is vise versa
Re: Balanceamento por oxirredução
OK, Thank you so muchChenBeier wrote: ↑Sat Apr 16, 2022 12:20 pm Yes there is a law
Acidic conditions
Reduction: if oxygen is in the reaction, then H+ is added on reactant side and water is obtained on product side
Oxidation is vise versa
Alkaline conditions
Reduction: if oxygen is in the reaction, then water is added on reactant side and OH- is obtained on product side
Oxidation is vise versa