A solution of 3.15 g of an acid dissolved in 100 g of benzene boils at 80.985 ℃ ( the boiling point of pure benzene is 80.099 ℃). A 0.2145- g sample of the same acid requires 45.22 ml of a 0.1054 M of sodium hydroxide(NaOH) solution for complete neutralization. Complete combustion of 1.004 g of the acid produced 0.9817 g of CO2 and 0.2007 g of H2O.
(a) Calculate the equivalent weight of the acid.
(b)Calculate the molecular weight and molecular formula of the acid.
(c)Write an electron dot formula for the acid.
I am working on this question. Any chemistry help will be accepted.
equivalent weight, molecular weight and formula for the unknown acid
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- Dhamnekar Winod
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equivalent weight, molecular weight and formula for the unknown acid
Last edited by Dhamnekar Winod on Fri Mar 11, 2022 4:07 am, edited 1 time in total.
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Re: equivalent weight, molecular weight and formula for the unknown acid
Answer is oxalic acid HOOC-COOH. Molar mass 90 g/ mol obtained by the boiling point difference of solution and solvent. Need ebullioscopic constant of Benzene 2,53 Kg K/mol for calculation
Combastion analysis gives ratio of C and H 1:1.
Neutralisation gives 4,766 mmol acid with the given mass it will be 45 g/ mol what means the acidity is the half of 90 g/ mol.
Combastion analysis gives ratio of C and H 1:1.
Neutralisation gives 4,766 mmol acid with the given mass it will be 45 g/ mol what means the acidity is the half of 90 g/ mol.
- Dhamnekar Winod
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Re: equivalent weight, molecular weight and formula for the unknown acid
Correct answer.
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]