Chemistry Forum

I have this balanced reaction:
Y₂O₃ + 6HNO₃ = 2Y(NO₃)₃ + 3H₂O
How I can determine the amount of HNO₃ (solvent)?
Thanks

You have a ratio 1:6 for Yttriumoxide and nitric acid. So you have to know how much Yttriumoxide you want to dissolve. You calculate the mole of it and know you need 6 times more of the nitric acid. According the concentration and specific gravity you can convert the mole of nitric acid to the volume.

Okay, So I have 0.002 mole of yttriumoxide that means I should have 0.012 mole of nitric acid, Please can you tell me how I can calculate the amount of nitric acid.

You need m = n* M ( moles time molar mass) this gives 100% HNO₃ , divided by the perecentage of it you get the Real mass and then V = m/σ. σ is specific gravity of nitric.

Thanks