Amount of solvent

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Talal
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Amount of solvent

Post by Talal »

I have this balanced reaction:
Y2O3 + 6HNO3 = 2Y(NO3)3 + 3H2O
How I can determine the amount of HNO3 (solvent)?
Thanks
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ChenBeier
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Re: Amount of solvent

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You have a ratio 1:6 for Yttriumoxide and nitric acid. So you have to know how much Yttriumoxide you want to dissolve. You calculate the mole of it and know you need 6 times more of the nitric acid. According the concentration and specific gravity you can convert the mole of nitric acid to the volume.
Talal
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Re: Amount of solvent

Post by Talal »

Okay, So I have 0.002 mole of yttriumoxide that means I should have 0.012 mole of nitric acid, Please can you tell me how I can calculate the amount of nitric acid.
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ChenBeier
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Re: Amount of solvent

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You need m = n* M ( moles time molar mass) this gives 100% HNO3 , divided by the perecentage of it you get the Real mass and then V = m/σ. σ is specific gravity of nitric.
Talal
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Re: Amount of solvent

Post by Talal »

Thanks
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