Chemistry Forum

Hello everyone, kinda need help understanding on this topic.
How do I calculate the percentage yield and theoretical yield of the product (cyclohexanol) ?
The weight of the product is = 1.502g
Volume of cylcohexanone is = 2mL
Using NaBH₄ and methanol

First develop the chemical reaction.
Then you can see how many mole of the keton correspond to the
Then convert the 2 ml into mole and calculate how much theoretically product can be obtained. Then also convert the obtained mass and compare.

ChenBeier wrote: ↑Mon Nov 08, 2021 9:51 am First develop the chemical reaction.
Then you can see how many mole of the keton correspond to the
Then convert the 2 ml into mole and calculate how much theoretically product can be obtained. Then also convert the obtained mass and compare.

Okay thank you
So does the equation be something like this?
C₆H₁₀O + 2 NaBH₄ = C₆H₁₁OH + 2 BH₃ + 2 Na

No,

Ok the keton get to alcohol is correct, but there will be nor sodium neither Borane obtained.

Product is sodiumborate.

But you know now that 1 mol keton gives 1 mol alcohol.

Now procedure the next step.

ChenBeier wrote: ↑Tue Nov 09, 2021 12:38 am No,

Ok the keton get to alcohol is correct, but there will be nor sodium neither Borane obtained.

Product is sodiumborate.

But you know now that 1 mol keton gives 1 mol alcohol.

Now procedure the next step.

Ohh i see its sodiumborate, thank you. But how do i convert 2ml to mole?

First you need specific gravity δ = m/V, convert this to mass, then convert with molar mass to mole.
n =m/M