Reduction of Cyclohexanone to Cylcohexanol

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darkaran
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Reduction of Cyclohexanone to Cylcohexanol

Post by darkaran »

Hello everyone, kinda need help understanding on this topic.
How do I calculate the percentage yield and theoretical yield of the product (cyclohexanol) ?
The weight of the product is = 1.502g
Volume of cylcohexanone is = 2mL
Using NaBH4 and methanol
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ChenBeier
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Re: Reduction of Cyclohexanone to Cylcohexanol

Post by ChenBeier »

First develop the chemical reaction.
Then you can see how many mole of the keton correspond to the
Then convert the 2 ml into mole and calculate how much theoretically product can be obtained. Then also convert the obtained mass and compare.
darkaran
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Re: Reduction of Cyclohexanone to Cylcohexanol

Post by darkaran »

ChenBeier wrote: Mon Nov 08, 2021 9:51 am First develop the chemical reaction.
Then you can see how many mole of the keton correspond to the
Then convert the 2 ml into mole and calculate how much theoretically product can be obtained. Then also convert the obtained mass and compare.
Okay thank you :)
So does the equation be something like this?
C6H10O + 2 NaBH4 = C6H11OH + 2 BH3 + 2 Na
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ChenBeier
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Re: Reduction of Cyclohexanone to Cylcohexanol

Post by ChenBeier »

No,

Ok the keton get to alcohol is correct, but there will be nor sodium neither Borane obtained.

Product is sodiumborate.

But you know now that 1 mol keton gives 1 mol alcohol.

Now procedure the next step.
darkaran
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Re: Reduction of Cyclohexanone to Cylcohexanol

Post by darkaran »

ChenBeier wrote: Tue Nov 09, 2021 12:38 am No,

Ok the keton get to alcohol is correct, but there will be nor sodium neither Borane obtained.

Product is sodiumborate.

But you know now that 1 mol keton gives 1 mol alcohol.

Now procedure the next step.
Ohh i see its sodiumborate, thank you. But how do i convert 2ml to mole?
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ChenBeier
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Re: Reduction of Cyclohexanone to Cylcohexanol

Post by ChenBeier »

First you need specific gravity δ = m/V, convert this to mass, then convert with molar mass to mole.
n =m/M
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