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### Reduction of Cyclohexanone to Cylcohexanol

Posted: **Mon Nov 08, 2021 4:30 am**

by **darkaran**

Hello everyone, kinda need help understanding on this topic.

How do I calculate the percentage yield and theoretical yield of the product (cyclohexanol) ?

The weight of the product is = 1.502g

Volume of cylcohexanone is = 2mL

Using NaBH_{4} and methanol

### Re: Reduction of Cyclohexanone to Cylcohexanol

Posted: **Mon Nov 08, 2021 9:51 am**

by **ChenBeier**

First develop the chemical reaction.

Then you can see how many mole of the keton correspond to the

Then convert the 2 ml into mole and calculate how much theoretically product can be obtained. Then also convert the obtained mass and compare.

### Re: Reduction of Cyclohexanone to Cylcohexanol

Posted: **Mon Nov 08, 2021 4:57 pm**

by **darkaran**

ChenBeier wrote: ↑Mon Nov 08, 2021 9:51 am
First develop the chemical reaction.

Then you can see how many mole of the keton correspond to the

Then convert the 2 ml into mole and calculate how much theoretically product can be obtained. Then also convert the obtained mass and compare.

Okay thank you

So does the equation be something like this?

C

_{6}H

_{10}O + 2 NaBH

_{4} = C

_{6}H

_{11}OH + 2 BH

_{3} + 2 Na

### Re: Reduction of Cyclohexanone to Cylcohexanol

Posted: **Tue Nov 09, 2021 12:38 am**

by **ChenBeier**

No,

Ok the keton get to alcohol is correct, but there will be nor sodium neither Borane obtained.

Product is sodiumborate.

But you know now that 1 mol keton gives 1 mol alcohol.

Now procedure the next step.

### Re: Reduction of Cyclohexanone to Cylcohexanol

Posted: **Tue Nov 09, 2021 2:42 am**

by **darkaran**

ChenBeier wrote: ↑Tue Nov 09, 2021 12:38 am
No,

Ok the keton get to alcohol is correct, but there will be nor sodium neither Borane obtained.

Product is sodiumborate.

But you know now that 1 mol keton gives 1 mol alcohol.

Now procedure the next step.

Ohh i see its sodiumborate, thank you. But how do i convert 2ml to mole?

### Re: Reduction of Cyclohexanone to Cylcohexanol

Posted: **Tue Nov 09, 2021 5:08 am**

by **ChenBeier**

First you need specific gravity δ = m/V, convert this to mass, then convert with molar mass to mole.

n =m/M