How to calculate the molarity of glacial acetic acid?

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Warner Mortensen
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How to calculate the molarity of glacial acetic acid?

Post by Warner Mortensen »

Glacial acetic acid is a colorless liquid with a clear appearance. Different companies offer concentrated glacial acetic acid with a purity of 99.7%

( density ) 1 L volume ⟶ ( mass of 1 L solution ) % by mass ⟶ ( mass of solute ) molar mass ⟶ ( number of moles ) 1 L volume ⟶ ( molarity )

The known values are:
The density of glacial acetic acid: 1.049 g / ml
The molecular weight of acetic acid ( CH3COOH ): 60.05 g / mole
The concentration of glacial acetic acid: ( 99.7 % )

Density = Weight Volume
Volume of 100 grams of glacial acetic acid = 1001.049 = 95.329 ml
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ChenBeier
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Re: How to calculate the molarity of glacial acetic acid?

Post by ChenBeier »

What is your question?
Warner Mortensen
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Re: How to calculate the molarity of glacial acetic acid?

Post by Warner Mortensen »

I solved this and wanted to share with others. Can you tell me this is correct or not and explain some more points?
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ChenBeier
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Re: How to calculate the molarity of glacial acetic acid?

Post by ChenBeier »

Its correct so far.
Only
Volume of 100 grams of glacial acetic acid = 1001.049 = 95.329 ml
is strange, what is 1001.049?

100 g correspond to 95,3 ml is correct.
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