P4+5O2→2P2O5.
I need to calculate what is the amount of 2P2O5 (and it is 4 mol)
The task says that there are 2mol of P4, so that means that i need 10mol of O2 for the reaction to happen, but how exactly do i predict that the amount of P2O5 is 4mol? What is the logic behind it?
Calculate the amount of substance
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- ChenBeier
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Re: Calculate the amount of substance
It's a given number. It can also 10, 0,5 98,67 mol or others
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Re: Calculate the amount of substance
No, the problem answer says this:
Knowing the amount of white phosphorus, the amount of phosphorus (V) oxide obtained is calculated according to the equation!
n P2O5=2*nP4=2⋅2mol=4mol , but i don't understand the logic behind this. This time the given number is that the white phosphorus is 2mol.
Knowing the amount of white phosphorus, the amount of phosphorus (V) oxide obtained is calculated according to the equation!
n P2O5=2*nP4=2⋅2mol=4mol , but i don't understand the logic behind this. This time the given number is that the white phosphorus is 2mol.
- ChenBeier
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Re: Calculate the amount of substance
Ok, it's a different question. Phosphorouspentoxide is existing bimolecular what means the real formula is P4O10.
The reaction is P4 + 5 O2 => P4O10 = 2 P2O5
But 4 mol is wrong, make no sense.
The reaction is P4 + 5 O2 => P4O10 = 2 P2O5
But 4 mol is wrong, make no sense.