Prediction of precipitation

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Dhamnekar Winod
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Prediction of precipitation

Post by Dhamnekar Winod »

The salt MX2 has a \(K_{sp}\) of 4.64e-9. If equal volumes of 0.00061 M M(NO3)2 and 0.001 M NaX are mixed, will solid form? M represents metal and X represents anion.

What is your answer? Yes or No? My answer is No.

I computed the answer as follows: Firstly, we have to determine the concentration of M and X after mixing them. As their volumes are equal, it will be half of the initial concentration.
\(Q_{ion}=0.000305* (2*0.0005)^2=3.05e-10\) which is less than the given \(K_{sp}=4.64e-9\), hence precipitation won't form.
Last edited by Dhamnekar Winod on Thu Jun 10, 2021 7:17 am, edited 1 time in total.
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Re: Prediction of precipitation

Post by ChenBeier »

Depends which kind of metal and which anion.
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