Salt and vinegar and penny experiment full balanced

Chemistry and homework help forum.

Organic Chemistry, Analytical Chemistry, Biochemistry, Physical Chemistry, Computational Chemistry, Theoretical Chemistry, High School Chemistry, Colledge Chemistry and University Chemistry Forum.

Share your chemistry ideas, discuss chemical problems, ask for help with scientific chemistry questions, inspire others by your chemistry vision!

Please feel free to start a scientific chemistry discussion here!

Discuss chemistry homework problems with experts!

Ask for help with chemical questions and help others with your chemistry knowledge!

Moderators: Xen, expert, ChenBeier

Post Reply
Cody199
Newbie
Newbie
Posts: 1
Joined: Sun May 09, 2021 5:37 pm

Salt and vinegar and penny experiment full balanced

Post by Cody199 »

Just looking to get to full balanced equation for the salt and vinegar and penny experiment
User avatar
ChenBeier
Distinguished Member
Distinguished Member
Posts: 1542
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

Re: Salt and vinegar and penny experiment full balanced

Post by ChenBeier »

Describe the experiment. What do you do with the penny.
Zmann0
Jr. Member
Jr. Member
Posts: 7
Joined: Mon May 17, 2021 7:24 am
Location: Minnesota, United States

Re: Salt and vinegar and penny experiment full balanced

Post by Zmann0 »

When the Acetic acid and Salt react they form Weak Hydrochloric acid which dissolves the Blue-Green Copper hydroxide leaving the New copper, vinegar is about 4-5% Acetic acid.

1. 2 CH3COOH + 2 NaCl = 2 HCl + 2 NaCH3COO
2. 2 HCl + Cu(OH)2 = 2 H2O & 2 CuCl
User avatar
ChenBeier
Distinguished Member
Distinguished Member
Posts: 1542
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

Re: Salt and vinegar and penny experiment full balanced

Post by ChenBeier »

That will do acetic acid by its own. Acetic acid is not able to create hydrochloric. Its to weak.

Cu(OH)2 + 2 CH3COOH => Cu(CH3COO)2 + 2 H2O

Chloride ion can be exchanged by the acetate

Cu(CH3COO)2 + 2 NaCl => CuCl2 + 2 CH3COONa
Post Reply