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Chemical equilibrium composition

Posted: Fri May 07, 2021 7:45 am
by marianajanuario
I'm doing a paper for a subject in college, being this subject combustion.
I need to write and balance the following chemical formula : 0.8NH3+0.2CH4=aNH3*bCH4*cH2*dN2+e*C , being a,b,c,d,e the coefficient of each species. Does anyone have any suggestion in how to do it?
Thank you!

Re: Chemical equilibrium composition

Posted: Fri May 07, 2021 7:55 am
by ChenBeier
You have ammonia and methane on educt side already why you should have it on product side again.
What kind of process is it.
At least you can make from 1 mole methane 2 mole hydrogen and 1 mole carbon.
Ammonia can be decomposed in the back reaction of Haber Bosch
2 mole ammonia give 1 mole nitrogen and 3 mole hydrogen.

a =0, b= 0, c = 1,6 , d= 0,4, e = 0,2 100% yield.
But with other envirement conditions everything can happen, even reaction of carbon, hydrogen and nitrogen together.