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please help me calculate stoichiometry

Posted: Mon Apr 05, 2021 1:48 am
by edig789
In some papers, 6.41KNO3 + 1.027C12H22O11 → 7.97H2O + 3.88CO2 + 3.205N2 + 6.06K2CO3

What I calculated is

48 KNO3 + 5 C12H22O11 = 36 CO2 + 55 H2O + 24 K2CO3 + 24 N2

How does the above equation come out?

Re: please help me calculate stoichiometry

Posted: Mon Apr 05, 2021 2:30 am
by ChenBeier
Yours is correct. Above they used broken numbers and also not very accurate i would say wrong calculation. Example 7.97 H2O never can come from 1.027 C12H22O11.

Re: please help me calculate stoichiometry

Posted: Mon Apr 05, 2021 6:03 am
by edig789
Thanks!! :D