please help me calculate stoichiometry
Posted: Mon Apr 05, 2021 1:48 am
In some papers, 6.41KNO3 + 1.027C12H22O11 → 7.97H2O + 3.88CO2 + 3.205N2 + 6.06K2CO3
What I calculated is
48 KNO3 + 5 C12H22O11 = 36 CO2 + 55 H2O + 24 K2CO3 + 24 N2
How does the above equation come out?
What I calculated is
48 KNO3 + 5 C12H22O11 = 36 CO2 + 55 H2O + 24 K2CO3 + 24 N2
How does the above equation come out?