Chemistry Forum

A 30,0 g de una muestra de ZnCl₂ se le agrega exceso de H₃PO₄ obteniéndose 15,5 g de Zn₃(PO₄)₂.

Calcule los equivalentes de H₃PO₄ que deben haber reaccionado si el rendimiento fue del 90,0 %

Excess H₃PO₄ is added to 30.0 g of a sample of ZnCl₂, obtaining 15.5 g of Zn₃ (PO₄) 2.

Calculate the H₃PO₄ equivalents that must have reacted if the yield was 90.0%

What is your own work. Where do you have problems.

I don't know how to get the excess H₃PO₄ ...
Idk to pose the first part of the problem

Excess means there is enough phosphoric acid.
First develop the chemical equation.
Then calculate the mol of zincphosphate .
Check is enough zinc chloride available.
From zinc phosphate calculate back how much phosphoric is needed.
Calculate with the yield.

Thank uuu