_{2}se le agrega exceso de H

_{3}PO

_{4}obteniéndose 15,5 g de Zn

_{3}(PO

_{4})

_{2}.

Calcule los equivalentes de H

_{3}PO

_{4}que deben haber reaccionado si el rendimiento fue del 90,0 %

**Moderators:** expert, ChenBeier, Xen

A 30,0 g de una muestra de ZnCl_{2} se le agrega exceso de H_{3}PO_{4} obteniéndose 15,5 g de Zn_{3}(PO_{4})_{2}.

Calcule los equivalentes de H_{3}PO_{4} que deben haber reaccionado si el rendimiento fue del 90,0 %

Calcule los equivalentes de H

Excess H_{3}PO_{4} is added to 30.0 g of a sample of ZnCl_{2}, obtaining 15.5 g of Zn_{3} (PO_{4}) 2.

Calculate the H_{3}PO_{4} equivalents that must have reacted if the yield was 90.0%

Calculate the H

- ChenBeier
- Distinguished Member
**Posts:**703**Joined:**Wed Sep 27, 2017 7:25 am**Location:**Berlin, Germany

What is your own work. Where do you have problems.

I don't know how to get the excess H_{3}PO_{4} ...

Idk to pose the first part of the problem

Idk to pose the first part of the problem

- ChenBeier
- Distinguished Member
**Posts:**703**Joined:**Wed Sep 27, 2017 7:25 am**Location:**Berlin, Germany

Excess means there is enough phosphoric acid.

First develop the chemical equation.

Then calculate the mol of zincphosphate .

Check is enough zinc chloride available.

From zinc phosphate calculate back how much phosphoric is needed.

Calculate with the yield.

First develop the chemical equation.

Then calculate the mol of zincphosphate .

Check is enough zinc chloride available.

From zinc phosphate calculate back how much phosphoric is needed.

Calculate with the yield.