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Maite2019
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Me podrian ayudar

Post by Maite2019 »

A 30,0 g de una muestra de ZnCl2 se le agrega exceso de H3PO4 obteniéndose 15,5 g de Zn3(PO4)2.

Calcule los equivalentes de H3PO4 que deben haber reaccionado si el rendimiento fue del 90,0 %
Maite2019
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Post by Maite2019 »

Excess H3PO4 is added to 30.0 g of a sample of ZnCl2, obtaining 15.5 g of Zn3 (PO4) 2.

Calculate the H3PO4 equivalents that must have reacted if the yield was 90.0%
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ChenBeier
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Post by ChenBeier »

What is your own work. Where do you have problems.
Maite2019
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Post by Maite2019 »

I don't know how to get the excess H3PO4 ...
Idk to pose the first part of the problem
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ChenBeier
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Post by ChenBeier »

Excess means there is enough phosphoric acid.
First develop the chemical equation.
Then calculate the mol of zincphosphate .
Check is enough zinc chloride available.
From zinc phosphate calculate back how much phosphoric is needed.
Calculate with the yield.
Maite2019
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Post by Maite2019 »

Thank uuu :D
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