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Molecular structure

Posted: Tue Mar 30, 2021 10:59 pm
by Dhamnekar Winod
What is the answer to the following question?

The potential energy of two charged particles at a certain distance can be found through the equation \(E= \frac{q_1q_2}{4\pi\epsilon_0 r}\) where 1)r is a distance

2)
\(q_1\) and \(q_2\) are the charges

3)\(\epsilon_0= 8.8541878e-12F/m\)

Using the above equation, I computed the potential energy of four electrons located at the apices of a tetrahedron at a distance of 2.0 Å = 6.92e-18 Joules.

I computed the potential energy of four electrons located at the four corners of a square with edges of 2.0 Å =4.61e-18 Joules.

As four electrons located at the four corners of a square have lower potential energy than the potential energy of a tetrahedron, itis more stable.
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