## Molecular structure

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Dhamnekar Winod
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### Molecular structure

What is the answer to the following question?

The potential energy of two charged particles at a certain distance can be found through the equation $$E= \frac{q_1q_2}{4\pi\epsilon_0 r}$$ where 1)r is a distance

2)
$$q_1$$ and $$q_2$$ are the charges

3)$$\epsilon_0= 8.8541878e-12F/m$$

Using the above equation, I computed the potential energy of four electrons located at the apices of a tetrahedron at a distance of 2.0 Å = 6.92e-18 Joules.

I computed the potential energy of four electrons located at the four corners of a square with edges of 2.0 Å =4.61e-18 Joules.

As four electrons located at the four corners of a square have lower potential energy than the potential energy of a tetrahedron, itis more stable.
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