Help Quick I have a test

Chemistry and homework help forum.

Organic Chemistry, Analytical Chemistry, Biochemistry, Physical Chemistry, Computational Chemistry, Theoretical Chemistry, High School Chemistry, Colledge Chemistry and University Chemistry Forum.

Share your chemistry ideas, discuss chemical problems, ask for help with scientific chemistry questions, inspire others by your chemistry vision!

Please feel free to start a scientific chemistry discussion here!

Discuss chemistry homework problems with experts!

Ask for help with chemical questions and help others with your chemistry knowledge!

Moderators: expert, ChenBeier, Xen

Post Reply
Ineedhelpwchem
Newbie
Newbie
Posts: 3
Joined: Fri Mar 26, 2021 7:10 am

Help Quick I have a test

Post by Ineedhelpwchem »

Using reference table G

1) How many grams of KClO3 are needed to saturate 50 grams of water at 90 degrees C?

2) If 60 grams of NaNO3 are dissolved in 100 grams of water at 20 degrees C, how many additional grams of NaNO3 are needed to saturate the solution at 60 degrees C?
User avatar
ChenBeier
Distinguished Member
Distinguished Member
Posts: 703
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

Re: Help Quick I have a test

Post by ChenBeier »

There is no reference table G.
Ineedhelpwchem
Newbie
Newbie
Posts: 3
Joined: Fri Mar 26, 2021 7:10 am

Re: Help Quick I have a test

Post by Ineedhelpwchem »

table g.gif
table g.gif (37.99 KiB) Viewed 95 times
Attachments
table g.gif
table g.gif (37.99 KiB) Viewed 95 times
User avatar
ChenBeier
Distinguished Member
Distinguished Member
Posts: 703
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

Re: Help Quick I have a test

Post by ChenBeier »

Read the curve.
In 1. case the intersection of the curve of KClO3 at 90 °C will be at 52 g. The question asks for 50 g water so its about the half 26 g.
In 2. case the intersection at 60 ° C of NaNO3 is at 125 g . 60 g is already in, so add 65 g more.
Ineedhelpwchem
Newbie
Newbie
Posts: 3
Joined: Fri Mar 26, 2021 7:10 am

Re: Help Quick I have a test

Post by Ineedhelpwchem »

Thank you!
Post Reply