stoichiometry
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stoichiometry
Calculate the mass of carbon dioxide formed (CO2, 44.01 g/mol) if 38.9 g acetylene, (C2H2, 26.04 g/mol) reacted completely with oxygen.
- Dhamnekar Winod
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Re: stoichiometry
The mass of carbon dioxide (CO2) formed if 38.9 g of acetylene(C2H2) reacted completely with oxygen(O2) is 65.74g.
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- ChenBeier
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Re: stoichiometry
Wrong result
- Dhamnekar Winod
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Re: stoichiometry
I think the reaction is 2C2H2 + 5O2 → 4CO2 + 2H2O
Now, mole ratio of acetylene and carbon dioxide is 1:2. Molar mass of CO2 is 44.0098 g/gmol. Molar mass of C2H2 is 26.0378 g/gmol.
38.9/26.04 = 1.494 mol of C2H2 produces 1.494*2 =mol of CO2. So, CO2 produced is 1.494 * 2*44.0098 = 131.50g.
I think, this would be a correct answer.
Now, mole ratio of acetylene and carbon dioxide is 1:2. Molar mass of CO2 is 44.0098 g/gmol. Molar mass of C2H2 is 26.0378 g/gmol.
38.9/26.04 = 1.494 mol of C2H2 produces 1.494*2 =mol of CO2. So, CO2 produced is 1.494 * 2*44.0098 = 131.50g.
I think, this would be a correct answer.
Last edited by Dhamnekar Winod on Thu Mar 25, 2021 5:01 am, edited 1 time in total.
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
- ChenBeier
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Re: stoichiometry
Yes key point is ratio C2H2 and CO2 is 1:2.
So the double amount has to be calculated, what means 131,5 g
So the double amount has to be calculated, what means 131,5 g