## acetic acid solution

Chemistry and homework help forum.

Organic Chemistry, Analytical Chemistry, Biochemistry, Physical Chemistry, Computational Chemistry, Theoretical Chemistry, High School Chemistry, Colledge Chemistry and University Chemistry Forum.

Share your chemistry ideas, discuss chemical problems, ask for help with scientific chemistry questions, inspire others by your chemistry vision!

Please feel free to start a scientific chemistry discussion here!

Discuss chemistry homework problems with experts!

Ask for help with chemical questions and help others with your chemistry knowledge!

Moderators: expert, ChenBeier, Xen

sue
Full Member
Posts: 13
Joined: Tue Mar 23, 2021 1:31 pm

### acetic acid solution

Calculate the ml that need to be transferred from a solution of 950ml CH 3 COOH at 48% by mass with a density of 1.05g / ml to prepare a solution at 1.28M in 250ml.

i dont understand
ChenBeier
Distinguished Member
Posts: 703
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

### Re: acetic acid calculation

Calculate backward how many moles is 1,28 M in 250 ml, this convert with the molar mass of acetic acid to the mass. This value dilute to 48 % and with the density you get the required volume.
sue
Full Member
Posts: 13
Joined: Tue Mar 23, 2021 1:31 pm

### Re: acetic acid solution

mmmmm thank you ?
ChenBeier
Distinguished Member
Posts: 703
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

### Re: acetic acid solution

What is wrong, what you dont understand. Start with the first one.
What is meant with 1.28 M
Dhamnekar Winod
Sr. Staff Member
Posts: 130
Joined: Sat Nov 21, 2020 10:14 am
Location: Mumbai[Bombay],Maharashtra State,India

### Re: acetic acid solution

If i am correct , 145.12 ml that need to be transferred from the solution of 950 ml of CH3COOH at 48% by mass with a density of 1.05 g/ml to prepare solution of 1.28 M in 250 ml.
Last edited by Dhamnekar Winod on Thu Mar 25, 2021 5:11 am, edited 1 time in total.
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
ChenBeier
Distinguished Member
Posts: 703
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

### Re: acetic acid solution

Wrong result
Dhamnekar Winod
Sr. Staff Member
Posts: 130
Joined: Sat Nov 21, 2020 10:14 am
Location: Mumbai[Bombay],Maharashtra State,India

### Re: acetic acid solution

I edited my answer from 152.5 ml to 145.12 ml. Is this correct?
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
ChenBeier
Distinguished Member
Posts: 703
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

### Re: acetic acid solution

No, show your calculation. But normaly Sue should do it.
Dhamnekar Winod
Sr. Staff Member
Posts: 130
Joined: Sat Nov 21, 2020 10:14 am
Location: Mumbai[Bombay],Maharashtra State,India

### Re: acetic acid solution

Here is my computational chemistry work

We have 950 ml of solution of CH3COOH.
The density of this solution is 1.05g/ml. CH3COOH is present 48% by mass in this solution. Mass of 950 ml of solution is 950 ml *1.05g= 997.50 g.

CH3COOH is 0.48 of 997.50 g. = 478.80 g. Molar mass of CH3COOH is 60.0524g/gmol. 478.8g/60.0524 g = 7.973 M of CH3COOH is present in 950 l of solution.

So, in 250 ml of its solution ,2.098 M of CH3COOH is present.

But we want to prepare solution of 1.28 M. Hence, we require $$152.51 ml =\frac{ 250 ml*2.098M}{1.28 M}$$ needs to betransferred from 950 ml of solution of CH3COOH
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
ChenBeier
Distinguished Member
Posts: 703
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

### Re: acetic acid solution

No that was not the question.
A solution of 250 ml 1.28 M should be prepared.
250 ml contain 1/4 = 0.32 mol. This calculated with the molar mass of 60 g/mol gives 19,2 g 100% what is equal 40 g 48%. With Density of 1.05 g/ ml it gives 38 ml.
Dhamnekar Winod
Sr. Staff Member
Posts: 130
Joined: Sat Nov 21, 2020 10:14 am
Location: Mumbai[Bombay],Maharashtra State,India