acetic acid solution

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sue
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acetic acid solution

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Calculate the ml that need to be transferred from a solution of 950ml CH 3 COOH at 48% by mass with a density of 1.05g / ml to prepare a solution at 1.28M in 250ml.

i dont understand :cry:
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ChenBeier
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Re: acetic acid calculation

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Calculate backward how many moles is 1,28 M in 250 ml, this convert with the molar mass of acetic acid to the mass. This value dilute to 48 % and with the density you get the required volume.
sue
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Re: acetic acid solution

Post by sue »

mmmmm thank you ?
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ChenBeier
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Re: acetic acid solution

Post by ChenBeier »

What is wrong, what you dont understand. Start with the first one.
What is meant with 1.28 M
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Dhamnekar Winod
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Re: acetic acid solution

Post by Dhamnekar Winod »

If i am correct , 145.12 ml that need to be transferred from the solution of 950 ml of CH3COOH at 48% by mass with a density of 1.05 g/ml to prepare solution of 1.28 M in 250 ml.
Last edited by Dhamnekar Winod on Thu Mar 25, 2021 5:11 am, edited 1 time in total.
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
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ChenBeier
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Re: acetic acid solution

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Wrong result
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Dhamnekar Winod
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Re: acetic acid solution

Post by Dhamnekar Winod »

I edited my answer from 152.5 ml to 145.12 ml. Is this correct?
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
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Re: acetic acid solution

Post by ChenBeier »

No, show your calculation. But normaly Sue should do it.
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Dhamnekar Winod
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Re: acetic acid solution

Post by Dhamnekar Winod »

Here is my computational chemistry work

We have 950 ml of solution of CH3COOH.
The density of this solution is 1.05g/ml. CH3COOH is present 48% by mass in this solution. Mass of 950 ml of solution is 950 ml *1.05g= 997.50 g.

CH3COOH is 0.48 of 997.50 g. = 478.80 g. Molar mass of CH3COOH is 60.0524g/gmol. 478.8g/60.0524 g = 7.973 M of CH3COOH is present in 950 l of solution.

So, in 250 ml of its solution ,2.098 M of CH3COOH is present.

But we want to prepare solution of 1.28 M. Hence, we require \(152.51 ml =\frac{ 250 ml*2.098M}{1.28 M}\) needs to betransferred from 950 ml of solution of CH3COOH
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Re: acetic acid solution

Post by ChenBeier »

No that was not the question.
A solution of 250 ml 1.28 M should be prepared.
250 ml contain 1/4 = 0.32 mol. This calculated with the molar mass of 60 g/mol gives 19,2 g 100% what is equal 40 g 48%. With Density of 1.05 g/ ml it gives 38 ml.
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Dhamnekar Winod
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Re: acetic acid solution

Post by Dhamnekar Winod »

Thanks for your correct answer.
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
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