Chromium (III) Complex Ion Seperatio

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beaker1995
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Chromium (III) Complex Ion Seperatio

Post by beaker1995 »

Hi there!

I am currently doing an experimentin which three Chromium (Iii) ions are to be seperated via exchange column chromatography.

At the begning of the procedure, To prepare a 25mL solution of 0.35M Tetraaquadichlorochromium (III) chloride, a certain amount of Chromium(III) chloride hexahydrate is weighted into a beaker, and 25mL of 0.002M perchloric acid is added to it using a graduated cylinder.
This "certain amount" is what I am set out to obtain.
I am aware that I must use stoichiometric calculations to retrieve this value. So, I begin with balancing the equation:

Cl3CrH12O6 + HClO4 → CrCl2(H2O)4+

This equation is unbalancable. I am wondering if there is a byproduct I am missing, or perhaps if I am using the wrong equation? I just need a second pair of eyes to look over this and maybe spot what I am doing incorrectly.

Anything helps :)
Thanks!
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ChenBeier
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Re: Chromium (III) Complex Ion Seperatio

Post by ChenBeier »

Why perchloric acid is used. Should it hydrochloric instead.

CrCl3 x 6 H2O => CrCl2( H2O)4+ + Cl- + 2H2O
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