Homework!! NEED HELP!

[chemistry123]

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[ChenBeier]

1.Some oxidation numbers has to be learned like vocabulary of a language.
Elements 0, even bonded together like O₂
Hydrogen +1 , in hydrides also -1
1. Group +1
2. Group +2
3. Group +3, heavy one also +1
4. Group +4, +2, -4, carbon have all from +4 to -4
5. Group +5, -3 Nitrogen all from +5 to -3
6. Group +6, -2, oxygen only +2 ,+1 -1, -2
7. Group +7 to -1, flourine only -1
8. Group 0, Kr,Xe,Rn also +8
The others can be calculated with this knowledge

Example N₂O₅

0 = 2 * x( N)+ 5*(-2)O => x(N) = + 5

Try the other by yourself
2. a Ammonium nitride ( NH₄)₃N is not existing, decompose to 4 NH₃
b. is not clear only one compound
c. Flourine will exchange the bromine even react with it, also iron will be oxidised

[Dhamnekar Winod]

Reaction in 2.c is \(2F + FeBr_2 \rightarrow FeF_2 + Br_2\)

[ChenBeier]

This is wrong . There is no 2 F.
Flourine is the strongest oxidiser so everthing will oxidised.

2 FeBr₂ + 9 F₂ => 2 FeF₃ + 4 BrF₃

[Dhamnekar Winod]

Thanks for correction. But can we write this reaction in this way also?
FeBr₂ + 4 F₂ => FeF₂ + 2 BrF₃

[ChenBeier]

You forget that iron also will oxidised from Fe 2+ to Fe 3+. Flourine will oxidise everything to high oxidation number.

[Dhamnekar Winod]

Okay, Thanks.