Arrangement of chemical compounds in order of increasing electric conductance

[Dhamnekar Winod]

Arrange the following in the order of increasing electrical conductance.
O₂H₂, Hf(II)H₂, BeH₂, SrH₂, CaH₂,TiH₂,TeH₂.

My answer: Electronegativity:- (H)=2.2, Be=1.6, Hf=1.3, O=3.4 Ca, Sr=1,Ti= 1.5

BeH₂<TiH₂<Hf(II)H₂<O₂H₂=CaH₂=SrH₂.

Is this answer correct?

[ChenBeier]

I dont think that any compound beside the hydrogen peroxide has an significant conductance, because all are solid. Maybe some can work as semiconductor.

[Dhamnekar Winod]

What do you think about this answer provided to me in respect of three of these seven compounds?

The electrical conductance of a molecule depends upon its ionic or covalent nature. Ionic compounds conduct, whereas covalent compounds do not.

BeH₂ is a covalent hydride. Hence, it does not conduct. CaH₂ is an ionic hydride, which conducts electricity in the molten state. Titanium hydride, TiH₂ is metallic in nature and conducts electricity at room temperature. Hence, the increasing order of electrical conductance is as follows:

BeH₂ < CaH₂ < TiH₂

Can we use Fajan's rules to decide the electric conductance of all of these seven compounds?

[ChenBeier]

I dont think so, most of them you have to melt to get conductivity.