Hi, I’m new here
I’m stuck on a i’m question, my teacher is asking me for the physical and chemical properties of this balanced equation PB(ClO3)4 + 2HgS = Pb2 + 4Hg(ClO3)
Chemical formula
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- ChenBeier
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Re: Chemical formula
The equation is not balanced also the products are wrong.
Check the soloubilities. In water the reaction cannot take place. Consider Chlorate is a oxidiser. Sulfid a reducer. Chlorate will be go to chloride, sulfide will change to sulfate. Lead will change to Pb^2+, mercury will be not touched and keep its oxidiation number.
Check the soloubilities. In water the reaction cannot take place. Consider Chlorate is a oxidiser. Sulfid a reducer. Chlorate will be go to chloride, sulfide will change to sulfate. Lead will change to Pb^2+, mercury will be not touched and keep its oxidiation number.
Re: Chemical formula
How will I balance Lead(iv) chlorate + Mercury (i) sulfide?
- ChenBeier
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Re: Chemical formula
It is mercury(II) slfide HgS. Mercury(I)sulfide would be Hg2S but in my knowledge it is not existing.
Also lead(IV)chlorate is not existing. Lead(IV) compounds very unstable.
But nevertheless. ClO3 - will go to Cl- , S^2- go to SO4 2-.
Pb^4÷ to Pb^2+.
Develop the part equations bei using O^2- and e-
Also lead(IV)chlorate is not existing. Lead(IV) compounds very unstable.
But nevertheless. ClO3 - will go to Cl- , S^2- go to SO4 2-.
Pb^4÷ to Pb^2+.
Develop the part equations bei using O^2- and e-