Determining calorimeter constant
Posted: Wed Jan 27, 2021 9:43 am
https://www.chemteam.info/Thermochem/Vi ... ant-02.mp4
My answer to the problem in the above video:
If the constant were zero, the final temperature of the water would be 45.0 °C. So the amount of heat used by the calorimeter to heat from 21.3 to 43.3 is:
(50.0) (4.184) (1.7) = 355.6 J.
Since the constant is Joules/degree, the constant is
355.6 J / 22.0 °C = 16.2 J/°C (to three sig figs).
I want to know which answer is correct? The answer given in the video or my answer with aforesaid working?
My answer to the problem in the above video:
If the constant were zero, the final temperature of the water would be 45.0 °C. So the amount of heat used by the calorimeter to heat from 21.3 to 43.3 is:
(50.0) (4.184) (1.7) = 355.6 J.
Since the constant is Joules/degree, the constant is
355.6 J / 22.0 °C = 16.2 J/°C (to three sig figs).
I want to know which answer is correct? The answer given in the video or my answer with aforesaid working?