The ionization constant of water and its ionic product

Chemistry and homework help forum.

Organic Chemistry, Analytical Chemistry, Biochemistry, Physical Chemistry, Computational Chemistry, Theoretical Chemistry, High School Chemistry, Colledge Chemistry and University Chemistry Forum.

Share your chemistry ideas, discuss chemical problems, ask for help with scientific chemistry questions, inspire others by your chemistry vision!

Please feel free to start a scientific chemistry discussion here!

Discuss chemistry homework problems with experts!

Ask for help with chemical questions and help others with your chemistry knowledge!

Moderators: expert, ChenBeier, Xen

Post Reply
User avatar
Dhamnekar Winod
Full Member
Full Member
Posts: 16
Joined: Sat Nov 21, 2020 10:14 am
Location: Mumbai[Bombay],Maharashtra State,India

The ionization constant of water and its ionic product

Post by Dhamnekar Winod »

The following equilibrium exists.\(H_2O(l)_{\text{acid}} +H_2O(l)_{\text{base}}\rightleftharpoons H_3O^+(aq)_{\text{Conjugate acid}} + OH^-(aq)_{\text{Conjugate base}}\)
The equilibrium constant\((K)=\frac{[H_3O^+][OH^-]}{[H_2O]}=[H^+][OH^-]=K_w=?\)




Now, how is \( (K_w)= {[H_3O^+][OH^-]}\)= (1.00e-7)² M =1.00e-14 M²
Any science consists of the following process. 1) See 2)Hear 3)Smell,if needed 4)Taste, if needed 5)Think 6)Understand 7)Inference 8)Take decision [Believe or disbelieve, useful or useless, true or false, cause or effect, any other criteria]
User avatar
ChenBeier
Distinguished Member
Distinguished Member
Posts: 493
Joined: Wed Sep 27, 2017 7:25 am
Location: Berlin, Germany

Re: The ionization constant of water and its ionic product

Post by ChenBeier »

Its because the dissociation is like this. In neutral water 10^-7 H+ and also the same amount of OH- in solution.
Post Reply