Hey everyone,
A stoichiometric fuel-air mixture flowing in a Bunsen burner forms a well-defined conical flame. The mixture is then made leaner. For the same flow velocity in the tube, how does the cone angle change?
Thanks in advance
a question about conical flame.
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Re: a question about conical flame.
A leaner mixture means a narower base to the cone - thus a smaller cross sectional area; a circle measured by radius. .
Flow rate is measured as volume per time unit.
For a cone, volume is measured as.
Hence if the same volume is flowing through a narrower base, the height of the cone will be pushed up; it will be inversely proportionate to the square of the radius.
If the height is pushed up so as the radius decreases, then the appeture will become accuter.
Code: Select all
A = π r{2}
Flow rate is measured as volume per time unit.
For a cone, volume is measured as
Code: Select all
V = π r{2} h/3
Hence if the same volume is flowing through a narrower base, the height of the cone will be pushed up; it will be inversely proportionate to the square of the radius.
If the height is pushed up so as the radius decreases, then the appeture will become accuter.
Code: Select all
tan(θ/2) = r/h
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how does the cone angle change?
Because volume flow in tube is in same ratio so height of the tube increase.
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Re: a question about conical flame.
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